When do I use these equations for calculating linewidths?

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SUMMARY

The discussion focuses on the correct equations for calculating linewidths based on the emission time. The equations presented include Δf=1/(Δt), Δf=1/(4πΔt), and Δf=1/(2Δt). The correct approach involves defining the lifetime and linewidth precisely, with the relationship Δτ = ħ/Γ being crucial. Ultimately, the derived equation for linewidth is Δf = 1/(2π Δτ), which integrates the concepts of Lorentzian line shapes and quantum mechanics.

PREREQUISITES
  • Understanding of quantum mechanics, specifically wavefunctions and decay processes.
  • Familiarity with the concept of linewidth and its relation to energy states.
  • Knowledge of the Lorentzian line shape and its mathematical representation.
  • Basic grasp of the Planck constant (ħ) and its significance in quantum equations.
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  • Research the derivation of the Lorentzian line shape in quantum mechanics.
  • Study the implications of the Planck constant (ħ) in quantum state lifetimes.
  • Learn about the relationship between frequency and time in quantum systems.
  • Explore advanced topics in quantum optics related to linewidth measurements.
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Physicists, quantum mechanics students, and researchers in optics who are looking to deepen their understanding of linewidth calculations and their applications in emission processes.

Gavroy
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hi

i am looking for the correct equation, that gives me the linewidth by knowing the time of the emission process.

so far, i found in the internet:

Δf=1/(Δt), Δf=1/(4πΔt) and Δf=1/(2Δt)

can you tell me, when i have to use which of these equations and maybe whether you think that these equations are correct?

sry for my english, still practising! ;-)
 
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Gavroy, Getting the factor right requires saying precisely what you mean by the lifetime and the linewidth. A decaying state is described by a wavefunction |ψ|2 ~ exp(-Γt/ħ), so the lifetime of the state may be defined as Δτ = ħ/Γ.

The shape of the line is a Lorentzian, 1/((E-E0)2 + (Γ/2)2) which reaches its half-height at E = E0 ± Γ/2, so the "width" in that sense is ΔE = Γ. All right now ΔE = ħ Δω = 2π ħ Δf, so putting it all together you get Δf = 1/(2π Δτ).
 

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