When does a sound echo not disturb its listener

  • Thread starter Thread starter randomgamernerd
  • Start date Start date
  • Tags Tags
    Echo Sound
Click For Summary

Homework Help Overview

The problem involves understanding the conditions under which an echo from a loudspeaker does not disturb listeners during a prayer meeting. It includes calculating the time interval between repeated sounds and considers the speed of sound in air.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the time taken for sound to travel to a wall and back, questioning the significance of the echo not disturbing the listener. There are attempts to relate the timing of the echo to the perception of sound by the listener.

Discussion Status

Participants have shared their calculations and interpretations regarding the timing of the echo. Some have provided insights into how the echo's timing relates to the listener's experience, while others have expressed appreciation for the explanations given. The discussion includes various perspectives on the problem without reaching a definitive conclusion.

Contextual Notes

There is an emphasis on understanding the implications of sound timing and echo perception, with references to practical methods for estimating sound speed. Participants also reflect on the assumptions regarding the distance and timing involved in the echo phenomenon.

randomgamernerd
Messages
139
Reaction score
4

Homework Statement

:[/B]


At a prayer meeting the disciples sing JAI RAM .The sound amplified by a loudspeaker comes back after reflection from a building at a distance of 80 m from the meeting. What maximum time interval can be kept between one JAI-RAM and the next JAI-RAM so that the echo does not disturb a listener sitting in the meeting. Speed of sound in air is 320 m s-1.

Homework Equations

: [/B]s/t =v

The Attempt at a Solution

:
I did a blind guess and worked out the problem as follows:
Time taken to go to the wall = Time taken to come back = 80/320 s
⇒ Time difference = 2 x 80/320 = 1/2s.
Answer matches with the one given in the text.
I just want to know significance of the line "echo does not disturb a listener"
 
Physics news on Phys.org
randomgamernerd said:

Homework Statement

:[/B]


At a prayer meeting the disciples sing JAI RAM .The sound amplified by a loudspeaker comes back after reflection from a building at a distance of 80 m from the meeting. What maximum time interval can be kept between one JAI-RAM and the next JAI-RAM so that the echo does not disturb a listener sitting in the meeting. Speed of sound in air is 320 m s-1.

Homework Equations

: [/B]s/t =v

The Attempt at a Solution

:
I did a blind guess and worked out the problem as follows:
Time taken to go to the wall = Time taken to come back = 80/320 s
⇒ Time difference = 2 x 80/320 = 1/2s.
Answer matches with the one given in the text.
I just want to know significance of the line "echo does not disturb a listener"

With that time difference, the echo will be heard at exactly the same time as the next JAI-RAM, so the listener may well be unaware of the echo at all - and thus "the echo does not disturb the listener".
 
PeterO said:
With that time difference, the echo will be heard at exactly the same time as the next JAI-RAM, so the listener may well be unaware of the echo at all - and thus "the echo does not disturb the listener".
oh, ok...thanks..
 
randomgamernerd said:
oh , ok...thanks..
A similar method can be used to estimate the speed of sound.
If you were to clap while standing 80m from a wall, the echo would return in approximately 0.5 seconds.
You can improve the accuracy of your timing, by clapping in rhythm with the echo (which you will find hard to hear when you clap exactly in time with it, but it is easy to hear of the echo arrives a tiny bit early / late, so you acn adjust your rate of clapping until it is just right).
While clapping in time, you have someone else time, say, 20 claps - and they might get a time of 9.85 seconds - showing that it was a tiny bit less than 0.5 seconds for a single sound to travel there and back.
You are thus in a position to make quite a reasonable calculation of the speed of sound, on that day, at that air temperature and that air pressure.
It wouldn't matter, to the method, if the wall was actually 77.45m away - it just makes the arithmetic a little more complicated.
 
PeterO said:
A similar method can be used to estimate the speed of sound.
If you were to clap while standing 80m from a wall, the echo would return in approximately 0.5 seconds.
You can improve the accuracy of your timing, by clapping in rhythm with the echo (which you will find hard to hear when you clap exactly in time with it, but it is easy to hear of the echo arrives a tiny bit early / late, so you acn adjust your rate of clapping until it is just right).
While clapping in time, you have someone else time, say, 20 claps - and they might get a time of 9.85 seconds - showing that it was a tiny bit less than 0.5 seconds for a single sound to travel there and back.
You are thus in a position to make quite a reasonable calculation of the speed of sound, on that day, at that air temperature and that air pressure.
It wouldn't matter, to the method, if the wall was actually 77.45m away - it just makes the arithmetic a little more complicated.
whoa...thAnks for enlightening me.
 

Similar threads

Replies
3
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 12 ·
Replies
12
Views
7K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
4K
  • · Replies 3 ·
Replies
3
Views
4K