When is m33 divisible by 36? (m is an integer).

[Silversonic]

Homework Statement

Work out the order of the following elements;

$33 \in Z_{36}$

The Attempt at a Solution

It's probably really simple. But this only happens when an integer times 33 is divisible by 36.

That is;

$33n = 36m$

Which I can re-arrange to find

$n = 36m/33$

Now, I can keep adding 36/33 in my calculator until I get an integer result, but surely there is an easier way? For example;

$33 \equiv -3mod36$

Which suggests that 36/3 = 12 is the order of 33. This is fine and dandy, but what happens when I get to a question like, find the order of

$15 \in Z_{36}$

Then

$15 \equiv -21mod36$

Which means I'm back to the same problem again. My modular arithmetic is fairly poor, so how would I work this out?

 

[LCKurtz]

Factor 36 into prime factors and think about what factors k must have for 36 to divide 33k.

 

[Silversonic]

36 = 3x3x2x2

33 = 11x3

So k must be 3x2x2 = 12.

Also

15 = 5x3

So k must be 3x2x2 = 12.


Thanks!