Where Do Knights Collide in a Physics Problem?

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SUMMARY

The problem involves two knights, Sir George and Sir Alfred, riding towards each other from a distance of 78.0 meters. Sir George accelerates at 0.257 m/s², while Sir Alfred accelerates at 0.389 m/s². The collision point is determined to be 31.03 meters from Sir George's starting position. The solution utilizes the equation x = V(0)t + (1/2)at² to calculate the time taken for each knight to reach the collision point.

PREREQUISITES
  • Understanding of kinematic equations, specifically x = V(0)t + (1/2)at²
  • Basic knowledge of acceleration and velocity concepts
  • Ability to solve quadratic equations
  • Familiarity with relative motion principles
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  • Study kinematic equations in-depth, focusing on their applications in collision problems
  • Learn about relative acceleration and its impact on motion
  • Explore graphical methods for visualizing motion and collision points
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This discussion is beneficial for physics students, educators, and anyone interested in understanding motion dynamics and collision analysis in classical mechanics.

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[SOLVED] Acceleration/Velocity Problem

Homework Statement



In an historical movie, two knights on horseback start from rest 78.0 m apart and ride directly toward each other to do battle. Sir George's acceleration has a magnitude of 0.257 m/s2, while Sir Alfred's has a magnitude of 0.389 m/s2. Relative to Sir George's starting point, where do the knights collide?


Homework Equations



x= V(0)t+ (1/2)at^2

Average Acceleration

Average Velocity

The Attempt at a Solution




Ok I'm first of having trouble finding out where to START in this problem. I decided the best move would to use x= V(0) + (1/2)at^2 to find out how long it would take the two horseback riders to cross all 78 m.

I got t= 24.64 seconds for George
and t= 20.03 seconds for Alfred

What I'm having trouble doing now is setting up an equation that would allow me to figureout when the two riders crashed into each other. Any thoughts?
 
Last edited:
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Hint: the relative accn between the two is the sum of the two accns. Keep George fixed.
 
ahhh good point. thanks to that hint i solved the problem- the answer was it took George 31.03 meters before the collision.

thanks a bunch
 
Last edited:

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