Where does the second collision occur between two gliders on an air track?

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Homework Help Overview

The problem involves two gliders on an air track, where a target glider is initially at rest and a projectile glider approaches it with a specified velocity. The scenario includes an elastic collision between the two gliders and a subsequent rebound of the target glider from a spring at the end of the track, leading to a second collision. The goal is to determine the distance from the end of the track where this second collision occurs.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the timing and distances involved in the collisions, with one participant breaking the problem into two stages and calculating velocities and distances. Another participant suggests equating times for both gliders to find the collision point. There are questions about the accuracy of the book's provided answer and potential errors in the textbook.

Discussion Status

The discussion is ongoing, with participants exploring different methods to approach the problem. Some express confidence in their calculations while questioning the textbook's accuracy. There is no explicit consensus on the correct answer, but productive dialogue is occurring regarding the assumptions and calculations involved.

Contextual Notes

Participants note potential discrepancies in the textbook answers and express interest in verifying their understanding through additional problems. There is mention of the book's edition and its historical context, suggesting it may contain errors.

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Homework Statement


A target glider, whose mass [itex]m_2[/itex] is 350g is at rest on an air track, a distance [itex]d =53cm[/itex] from the end of the track. A projectile glider whose mass [itex]m_1[/itex] is 590g approaches the target flider with velocity [itex]v_{1i} = -75 cm/s[/itex] and collides elastically with it. The target glider rebounds elastically from a short spring at the end of the track and meets the projectile glider for a second time. How far from the end of the track does this second collision occur?

Homework Equations



Elastic collision [itex]KE_{i} = KE_{f}[/itex]
[tex]v_{1f} = \frac {m_1 - m_2}{m_1 + m_2} v_{1i}[/tex]
[tex]v_{2f} = \frac {2 m_2}{m_1 + m_2} v_{1i}[/tex]

The Attempt at a Solution



I broke it down into 2 separate stages, a [itex]t_1[/itex] from when [itex]m_2[/itex] goes from its starting point to the wall (a distance of [itex]d[/itex]) and a [itex]t_2[/itex] from when [itex]m_2[/itex] rebounds from the wall and collides with [itex]m_1[/itex] again.

[tex]v_{1f} = \frac {m_1 - m_2}{m_1 + m_2} v_{1i} = \frac {.590kg - .350 kg}{.590kg + .350kg} \times -.75m/s = -.19 m/s[/tex]

[tex]v_{2f} = v_{2f} = \frac {2 m_2}{m_1 + m_2} v_{1i} = \frac { 2x.350kg}{.590kg + .350kg} \times -.75m/s = -.55 m/s[/tex]

[tex]t_1 = \frac {x}{v_{02}} = \frac {.53m}{.55m/s} = .96s[/tex]

[tex]x_1 = v_{01}t = (.19)(.96) = .18m[/tex]

So in time interval [itex]t_1[/itex] the collision occurs and accelerates [itex]m_2[/itex] from rest to .55 m/s and [itex]m_1[/itex] is still moving at .19 m/s. It takes .96 seconds for [itex]m_2[/itex] to go [itex]d[/itex] and reach the end of the track and in this time [itex]m_1[/itex] moves .18m. Then [itex]m_2[/itex] has an elastic collision with the short spring and now has a velocity of [itex]v_{2f}[/itex].

Now:

[tex]x_2 = v_{02} t[/tex]
[tex]x_1 = v_{01}t + x_{01}[/tex]

Setting these equal when they collide and solving for [itex]t[/itex]:

[tex]t_2 = \frac {x_{01}}{v_{02} - (-v_{01})} = \frac{.53m - .18m}{.55m/s + .19 m/s} = .47s[/tex]

[tex]x_2 = v_{02}t = (.55)(.47) = .26m[/tex]

I feel confident this is the correct answer; however, the book says they collide the second time at .35m. [itex]m_1[/itex] was at .35m when [itex]m_2[/itex] collided with the wall at the end of the track. I think the book may have gotten those answers confused. Or I did something incorrectly, but then I don't know what it is. Is this the correct answer?
 
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heres how i did: assuming your numbers are right and both moving towards end;

equate times for two sliders at which collision occurs, (I omitted units cm and cm/s)

53/55+(53-Y)/55=y/19 where y is the distance traveled by slower block after collision

solving above, gives approx 27cm, and the distance to end= 53-27=26
 
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Agreed that the book is wrong again? I'm using halladay resnick walker fundamentals of physics. Does anybody know of more errors in the book? I'm not in an actual physics class, I'm just freelancing doing problems in my spare time so the answers in the back are the only way to know I'm understanding the material.
 
Assuming your velocities are right, and that's my recollection of the elastic case w/o looking it up, yea an error. That text has been around since I went to undergrad school, I should think it would be nearly error free, course they muct update their problems periodically.

You may want to pick up the Zen Of Physics, 3000... for like 15.00 Not a stand alone text, but if you want a lot of problems to check your methods, good investment IMO.
 
What is the title called exactly? I am interested...:-p
 
Fundamentals of physics
Fifth edition

Halliday resnick walker
 
The question was for Denverdoc, what is the exact title of the book and where can I purchase it?
 

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