Which Compound Is Less Stable?

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Discussion Overview

The discussion revolves around the stability of two chemical compounds presented in a general chemistry context. Participants explore the factors influencing stability, particularly focusing on formal charges and oxidation states, while seeking clarification on the structural representations of the compounds.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested, Homework-related

Main Points Raised

  • One participant identifies a compound as less stable based on formal charges and the presence of hydrogen atoms bonded to carbon.
  • Another participant questions the structural representation, specifically whether the top carbon has a hydrogen atom attached.
  • A different participant clarifies that the top structure lacks hydrogens on the carbons and offers to illustrate the lone pairs for better understanding.
  • One participant introduces the concept of oxidation states, noting that they involve rules for calculation that consider both formal charge and the types of atoms bonded to the central atom, suggesting a more complex evaluation of stability.

Areas of Agreement / Disagreement

Participants express differing views on the stability of the compounds based on formal charges and structural representations. The discussion remains unresolved regarding which compound is definitively less stable.

Contextual Notes

Participants highlight potential limitations in understanding due to the structural representations and the need for clarity on hydrogen counts and lone pairs. The discussion also indicates a dependence on definitions of formal charge and oxidation states.

Who May Find This Useful

Students studying general chemistry, particularly those interested in chemical stability, formal charges, and oxidation states.

mnnob07
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below are two simple compounds. this is from a first semester general chemistry test and there were four compounds total all with the same number of C H and O we had to tell which one was least stable and why.

I don't remember the other two because both had a formal charge of 0 on everything while these two had a +1 on the O (most of the time not a good sign) and -1 on the C.

I picked the first one as less stable because of the formal charges and because I was used to seeing the hydrogen atoms bonded to the C.

Can anyone tell me if I was right and what is the best way to approach these problems aside from straight formal charges?
 

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Does the top carbon have a hydrogen on it? Please make sure that all structures have the right numbers of hydrogen.
 
What do you mean? notice that there are two structures separated by a bit of whitespace. The top structure has no hydrogens on the carbons. Would you like me to draw the lone pairs?
 
I drew the lone pairs on the top one:
 

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This problem is a test of your understanding of the concept of oxidation states - there a rules in calculating these values and it does involve considering the formal charge - oxidation states also takes into account the type of atoms that a particular central atom is bonded to as well as its bonding arrangement while formal charge takes into account soley the bonding arrangement of the particular atom.
 
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