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Which of these simpifications is correct?

  1. May 1, 2006 #1
    i have dy/dx = 2t/(12t^2+2t)

    and i dont know whether the (2t) cancels out to give 1/(12t^2)

    or if i should factorise it thus:

    2t/(12t^2+2t) = t(2)/t(12t +2) = 2/12t + 2 = 1/(6t+2)

    help please!
  2. jcsd
  3. May 1, 2006 #2
    It should be [tex]\frac{1}{6t+1}[/tex]
  4. May 1, 2006 #3
    [tex]\frac{dy}{dx} = \frac{2t}{12t^2+2t} = \frac{2t}{2t(6t+1)} = \frac{1}{6t+1}[/tex]
  5. May 1, 2006 #4
    whoops, well i meant to write 1/6t + <B>1</B>...

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