Quadratic equation: Which way is correct? pic1 or pic2?

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Homework Help Overview

The discussion revolves around the resolution of a quadratic equation, specifically comparing two methods illustrated in images referred to as pic 1 and pic 2. The original poster expresses confusion regarding the validity of each method, particularly in relation to the treatment of absolute values and the conditions under which solutions are derived.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the correctness of two different methods for solving a quadratic equation, questioning the implications of removing absolute values and the conditions under which solutions are valid. Some participants suggest that both methods yield the same results, while others express concern about potential errors or inconsistencies in reasoning.

Discussion Status

The discussion is ongoing, with various participants offering observations and critiques of the methods presented. Some guidance has been provided regarding the nature of square roots and the conventions used in mathematical notation, but no consensus has been reached on which method is definitively correct.

Contextual Notes

Participants note that the original poster did not clearly present the problem, which may hinder understanding. Additionally, there is mention of a forum policy discouraging the posting of images, as they can be difficult to interpret.

  • #31
As the convention
\sqrt{}
denotes nonnegative square root , e.g. 2 out of 2,-2 which are square roots of 4.

That is OK but I am puzzled in using this symbol for negative or complex numbers.
For an example
\sqrt{-1}=i
Why not -i ? What is the convention ? I suppose it is "nonnegative on pure imaginary axis". Is it right?
Square roots of i are ##e^{\pi/4\ i},e^{5\pi/4\ i}##. Which is ##\sqrt{i}## ?
 
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  • #32
anuttarasammyak said:
That is OK but I am puzzled in using this symbol for negative or complex numbers.
For an example
\sqrt{-1}=i
Why not -i ? What is the convention ? I suppose it is "nonnegative on pure imaginary axis". Is it right?
Square roots of i are ##e^{\pi/4\ i},e^{5\pi/4\ i}##. Which is ##\sqrt{i}## ?
"Nonnegative on pure imaginary axis" seems to be the convention. For your second question, several web sites I looked at (search on "principal square root of a complex number") define the principal square root of a complex number as the root with a positive imaginary part. It's important to note that the imaginary part is the coefficient (a real number) of i. This would make ##e^{\pi/4 i}## the principal square root of i.
 
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  • #33
Thank you so much @Mark44 .

So we may summarize the convention of ##\sqrt{}## that we choose from square roots
#1 nonnegative one on imaginary axis
If imaginary part are zero,
#2 nonnegative one on real axis.
Or in a word it has phase angle of ##\phi[0,\pi)##.

\sqrt{e^{i5\pi/4}}=e^{i5\pi/8}
whose real part is negative and imaginary part is positive. Imaginary axis prevails.
 
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