Why choose a rectangular surface for flux calculation near a wire?

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darksyesider
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Homework Statement



http://web.mit.edu/viz/EM/visualizations/coursenotes/modules/guide10.pdf

pg: 10-17


Homework Equations





The Attempt at a Solution




I do not understand conceptually, why we chose the rectangular surface to take the flux over. Can anyone explain this please? i am having great trouble with it.

thank you.
 
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It just makes it easy mathematically to demonstrate the calculation. Any other weird shape will need numerical techniques to do the integral.