Why Does a Slinky Show a Sine Wave When Measuring Magnetic Fields?

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SUMMARY

The discussion centers on the observation of a sine wave pattern when measuring the magnetic field within a slinky using alternating current (AC). The magnetic field (B) inside the coil is approximated by the formula B = μ₀ I N, where N represents the number of turns and I is the current. In an AC circuit, the current can be expressed as I₀ = (V₀/|z|)sin(ωt + φ), with φ determined by φ = tan(χₗ/R) and χₗ = ωL. This indicates that the sine wave pattern is a direct result of the alternating nature of the current supplied to the slinky.

PREREQUISITES
  • Understanding of electromagnetic theory, specifically the wave equation for electromagnetic waves.
  • Familiarity with alternating current (AC) circuits and their characteristics.
  • Knowledge of magnetic field calculations, particularly using the formula B = μ₀ I N.
  • Basic grasp of trigonometric functions as they relate to waveforms.
NEXT STEPS
  • Study the principles of electromagnetic waves and their mathematical representations.
  • Learn about the characteristics and behavior of alternating current (AC) circuits.
  • Explore the derivation and application of the formula B = μ₀ I N in different contexts.
  • Investigate the role of phase angle (φ) in AC circuits and its impact on waveforms.
USEFUL FOR

Physics students, educators, and anyone interested in the practical applications of electromagnetic theory and AC circuits in experimental settings.

torquey123
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I'm trying to do this lab in physics where we are using sensors to find the magnetic field within a slinky with a current flowing through. Our graph(of time vs.magnetic field) keeps coming out as a sine wave. Is the wave equation for an electromagnetic wave applicable to find the magnitude of the magnetic field? My teacher and I are both a little bit confused, so some guidance would be appreciated. Thanks!
 
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did you plug the slinky into the wall ? the mains power supply is alternating current.

the b field inside the coil is approximated by

[tex]B= \mu _o I N[/tex]
where N is the number of turns and I is the current. in an AC circuit I would be

[tex]I_o = \frac{V_o}{|z|}sin(\omega t +\phi)[/tex] where [tex]\phi[/tex] is determined by
[tex] \phi = tan(\frac{\chi_L}{R})[/tex]
and
[tex]\chi _L = \omega L[/tex]

if you don't understand of this say so and i will try to explain
 
Last edited:

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