Why does lamp N get brighter when lamp M breaks?

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Homework Equations


Power = VI

The Attempt at a Solution


[/B]
Since lamp M breaks, lamp L gets more of the current so its brightness increases and lamp N's brightness stays the same because the current at point 2 is the same if the other lamp breaks or not, so N's brightness should not be affected.

So my answer is A but the correct answer is D?? What have I done wrong?
 
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ravsterphysics said:
View attachment 110973

Homework Equations


Power = VI

The Attempt at a Solution


[/B]
Since lamp M breaks, lamp L gets more of the current so its brightness increases and lamp N's brightness stays the same because the current at point 2 is the same if the other lamp breaks or not, so N's brightness should not be affected.

So my answer is A but the correct answer is D?? What have I done wrong?
The current through N will also change, as the resultant resistance changes when lamp M breaks.
 
ehild said:
The current through N will also change, as the resultant resistance changes when lamp M breaks.

I get it now.

since the parallel combo is no more, resistance has increased across the circuit so less current for both, so N decreases but L increases since it has more current in resistance than in parallel. Thanks.
 
It is correct, but can you derive what are the powers on the lamps in both cases, to prove your statement? The EMF of the battery is E and each lamp has resistance r.