How High Can You Jump on Phobos and How Long Does It Take?

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SUMMARY

On the Martian moon Phobos, the acceleration due to gravity is 0.001g, significantly lower than Earth's 1g. A person who can jump 2 meters on Earth can leap approximately 2000 meters on Phobos due to the reduced gravitational force. The time taken to reach maximum altitude can be calculated using kinematic equations, specifically V = at and x = 1/2at². Utilizing conservation of energy provides a valid approach to solving the problem, confirming that the same potential energy can be achieved in different gravitational fields.

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Homework Statement


At the surface of the Martian moon Phobos, the acceleration due to gravity is .001g, where g is the acceleration due to gravity on earth. If you can jump 2 m high on earth, how high can you leap on Phobos? How long would it take you to reach your maximum altitude?


Homework Equations





The Attempt at a Solution


I tried to solve this using the kinematic equations so I first tried to find the time at the top of the persons jump by using V = at and then plug that into the equitation x = 1/2at^2. The problem is that the first equation, when I plugged in the numbers I got t = 0.
 
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Try using conservation of energy.

To me it seems like you should be able to jump to the same potential energy in either field (because your legs can do the same amount of work)
I am not 100% sure if this is a valid approach, but it's worth a shot
 
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Nathanael said:
Try using conservation of energy.

To me it seems like you should be able to jump to the same potential energy in either field (because your legs can do the same amount of work)



I am not 100% sure if this is a valid approach, but it's worth a shot
It worked! Thanks!
 

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