Why Does Na2CO3 Result in a Basic Solution in Water?

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Na2CO3 results in a basic solution when dissolved in water due to the presence of the carbonate ion (CO32-), which undergoes hydrolysis. The carbonate ion reacts with water, producing bicarbonate (HCO3-) and hydroxide ions (OH-), leading to an increase in pH. The sodium ion (Na+) does not affect the acidity or basicity of the solution. The bicarbonate ion can also participate in further reactions, contributing to the basicity. Overall, the hydrolysis of CO32- is the key process that makes the solution basic.
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Homework Statement



Explain why Na2CO3 gives a basic solution when dissolved in water.

The Attempt at a Solution



The cation is Na+ while the anion is CO32-. The cation has no affinity for neither protons nor hydroxide ions. The anion should have basic properties to make a basic solution. Does this mean that HCO3- is a weak acid? I cannot find it in my table of weak acids.
 
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Why basic? To be brief: Hydrolysis. HCO3-, is from Carbonic acid. Carbonic acid is a diprotic acid, and when you look for the dissociation constant you need to look for the one for carbonic acid which will show you the values for the first AND the second dissociations.

Carbonic Acid: \[<br /> H_2 CO_3 <br /> \]<br />

the first dissociation is stronger than the second dissociation.
 
kasse said:

Homework Statement



Explain why Na2CO3 gives a basic solution when dissolved in water.

The Attempt at a Solution



The cation is Na+ while the anion is CO32-. The cation has no affinity for neither protons nor hydroxide ions. The anion should have basic properties to make a basic solution. Does this mean that HCO3- is a weak acid? I cannot find it in my table of weak acids.

The pertinent reactions you need to conceptualize are:

1) CO3-2 + H2O <-------> HCO3- + OH-

and,

2) HCO3- + H2O <-----> H2CO3 + OH-
 

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