Why Does Steepness in a Potential Energy Graph Indicate Greater Force?

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The discussion centers on the relationship between steepness in a potential energy graph and the magnitude of force acting on a particle. Participants identified regions Q, W, and T on the graph, concluding that region W exhibits the greatest force magnitude. This conclusion is based on the understanding that if the force is repulsive, potential energy decreases with distance, making W the highest potential. Conversely, if the force is attractive, T would have the highest potential, but the problem's ambiguity regarding the nature of the force complicates definitive answers.

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A plot of a graph describes the potential energy of a particle, due to the force exerted on it by another particle, as a function of distance. At which three regions (Q), (W), (T) would the magnitude of force on the particle be the greatest? and why?

[T]
(T) is suppose to be located the most (=) on the x axis





-(0)----------------[Q]---------------------------…


[W]

The answer Is (W)
Why?

I answered (T) because I thought it had the greatest magnitude and being the farthest (+) value on both the y and x axis
 
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If the force is repulsive, as in like charges, then potential decreases with distance, and W would have the highest potential. If the force is attractive, as in gravity or opposing charges, potential increases with distance, and T would have the highest potential.

The problem statement doesn't specify if the force is repulsive or attractive, so it really can't be asnwered as worded.
 

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