taffer33
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Concrete for example - you need less concrete to obtain the same lead equivalent for photon energy 500 keV than for 200 keV. What is the reason for this?
The effectiveness of low-Z shielding, such as concrete, increases with photon energy due to the predominance of the Compton Effect at higher energies. For instance, less concrete is required to achieve the same lead equivalent at 500 keV compared to 200 keV. This phenomenon is attributed to the mass attenuation coefficient decreasing with increasing gamma energy, while the mass energy-absorption coefficient shows a slight increase between 0.2 to 0.5 MeV. The elemental absorption edge of lead at approximately 88 keV also plays a significant role in this behavior, as the photo-ionization cross-section decreases with higher photon energies, aligning more closely with that of concrete.
PREREQUISITESPhysicists, radiation safety officers, and engineers involved in designing shielding for medical imaging facilities, particularly those working with PET technology and gamma radiation.
It's a property of lead rather than a property of the concrete.taffer33 said:https://archive.org/details/jresv38n6p665
it's in this article for example
I asked this question as I was reading about shieldings in PET departments, where they suggest lead/concrete ratio 12-15, while ratio for 150 keV X-Ray is 80... (These are example regulations from my country).