Why doesn't Mathematica compute InverseFunction for (2x+1)/(x-1)?

[roam]

I'm trying to find the inverse of a function, for instance: f(x)=(2x+1)/(x-1) using Mathematica but it doesn't produce any answers.

This is my input:

> f(x)=(2x+1)/(x-1)

> InverseFunction[f]

The output is always something like:

"InverseFunction[(1+2x)/(-1+x)]"

So, does anyone know what the problem is?

Thanks,

 

[Dale]

InverseFunction only evaluates for built-in functions like trig functions. I think you want:
Solve[y == (2 x + 1)/(x - 1), x]

 

[roam]

Oh I see... Thank you!

 

[iremcangun]

Thank you very much roam, you've helped me to solve a big problem.