Why is a equal to negative a in this scenario?

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SUMMARY

The discussion centers on the mathematical property that leads to the conclusion that \( a \) is equal to \( -a \) under specific conditions involving square roots. The user explores the equation \( \sqrt{a} = \sqrt{b-c} \) and identifies the critical step where the property \( \sqrt{ab} = \sqrt{a}\sqrt{b} \) is applied incorrectly due to the non-negativity restriction on \( a \) and \( b \). This results in the expression \( a = \pm a \), necessitating a decision on the correct sign based on context.

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  • Understanding of complex numbers, specifically the imaginary unit \( i \).
  • Familiarity with square root properties and their restrictions.
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  • Study the properties of square roots, particularly the conditions under which \( \sqrt{ab} = \sqrt{a}\sqrt{b} \) holds true.
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noahsdev
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I've been messing around with numbers (as you do) and I'm wondering why this occurs..
lets let a = b-c.
√a
= √(b-c)
=√(-(c-b))
=i√(c-b)
=i√(-(b-c))
=i2√(b-c)
=-√(b-c)
=-√a
For example if you let a = 1, b = 2, and c = 1.
 
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noahsdev said:
I've been messing around with numbers (as you do) and I'm wondering why this occurs..
lets let a = b-c.
√a
= √(b-c)
=√(-(c-b))
=i√(c-b)
The step above is where the problem is. You're using the property that ##\sqrt{ab} = \sqrt{a}\sqrt{b}##
There are restrictions on this and some of the other square root properties - both a and b have to be nonnegative.
noahsdev said:
=i√(-(b-c))
=i2√(b-c)
=-√(b-c)
=-√a
For example if you let a = 1, b = 2, and c = 1.
 
Last edited:
Mark44 said:
The step above is where the problem is. You're using the property that ##\sqrt{ab} = \sqrt{a}\sqrt{b}##
There are restrictions on this and some of the other square root properties - both a and b have to be nonnegative.
That makes sense. Thanks.
 
\sqrt[2]{-1} = \pm i. The choice of the '+' or '-' depends on the situation. So your result is 'a = \pm a' where you must decide which sign is correct.
 

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