Why is an octahedral complex optically active despite having a plane of symmetry?

[Vishesh Jain]

Homework Statement

i'm having a complex which has plane of symmetry but still seems optically active

Relevant Equations

please see the figure and description

Shown above is an octahedral coordination complex and it's mirror image. The complex has a plane of symmetry (shown in the left diagram, a diagonal plane passing through bottom left and top right corner, perpendicular to the square plane) ... but still it's mirror image is non-superimposable ... i.e it is an optically active compound .. how is it possible or where is my mistake ?

 

[Ygggdrasil]

If you rotate the mirror image 90° clockwise about the vertical axis, you can superpose it with the original compound.

 

[Vishesh Jain]

Oh yea .. thanks :-) !