oktovan
- 2
- 0
Is there any other elements that can be used for fusion?
The discussion revolves around the reasons why hydrogen isotopes, particularly deuterium and tritium, are primarily used for fusion in bombs. Participants explore the conditions required for fusion, the practicality of using other elements, and the implications of different fusion reactions.
Participants express a range of views on the practicality and efficiency of using different isotopes and elements for fusion. There is no consensus on the superiority of one approach over another, and multiple competing perspectives remain throughout the discussion.
Participants highlight the challenges of achieving fusion with elements heavier than hydrogen and helium, emphasizing the extreme conditions required for such reactions. The discussion also touches on the implications of energy release in different fusion processes.
This discussion may be of interest to those studying nuclear physics, fusion technology, or the processes occurring in stellar environments.
Drakkith said:The easiest material to get to fusion is tritium and deuterium. Lithium is used because during the multi-stage process of detonation, it is turned into tritium.
mesa said:So the Li6 gets hit by a neutron and breaks into a tritium and two deuterium isotpoes or some other arrangement of the nuetrons and protons?
oktovan said:Is there any other elements that can be used for fusion?
Drakkith said:The easiest material to get to fusion is tritium and deuterium. Lithium is used because during the multi-stage process of detonation, it is turned into tritium.
mfb said:Drakkith's statement is true, as D+T (one proton each) is easier than any reaction with helium (2 protons) or even heavier nuclei. The advantage of helium-3 is the possibility to have a fusion reaction without (free) neutrons.
tasp77 said:You also have less energy released per pair of nuclei fused as you go from hydrogen to iron. Even if it turned out to be 'relatively' easy to fuse neon into calcium (to cite a fanciful example), the expected energy pay off for the reaction would be low.