Why is it wrong to conclude a isn't the vertice (conics)

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Homework Statement



Given the ellipse is centered at the origin and the information, find an equation of the ellipse.

1) An ellipse with focus ([tex]\sqrt{5}[/tex],0), directrix; x = [tex]\frac{9}{\sqrt{5}}[/tex]

2) An ellipse with an eccentricity of 4/5




The Attempt at a Solution



I have to leave right now so I can't post a usuall good attept, but basically for #1) you cannot match the directrix with the a/e, but for #2) you are supposed to take the focus = 4
 
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flyingpig said:
but for #2) you are supposed to take the focus = 4
Hate to be picky, but a focus is a point, not a number. If
e = c/a,
where c is the distance from the center to a focus, and a is the distance from the center to a vertex (not vertice!), then you should know what a is. All it remains is for you to find b, the distance from the center to an endpoint of the minor axis, and you're done.
 
eumyang said:
Hate to be picky, but a focus is a point, not a number. If
e = c/a,
Yes, flyingpig knows that. He intended [itex]\left(\sqrt{5}, 0\right)[/itex] but, for some reason had only the squareroot in LaTeX and on a separate line.

where c is the distance from the center to a focus, and a is the distance from the center to a vertex (not vertice!), then you should know what a is. All it remains is for you to find b, the distance from the center to an endpoint of the minor axis, and you're done.
Good!
 
HallsofIvy said:
Yes, flyingpig knows that. He intended [itex]\left(\sqrt{5}, 0\right)[/itex] but, for some reason had only the squareroot in LaTeX and on a separate line.
Actually, I was referring to #2, where he writes:
flyingpig said:
I have to leave right now so I can't post a usuall good attept, but basically for #1) you cannot match the directrix with the a/e, but for #2) you are supposed to take the focus = 4 (emphasis mine)