Why is $M/(N\cap P)$ Artinian when $M/N$ and $M/P$ are Artinian?

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    2016
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SUMMARY

The discussion centers on the proof that if $M/N$ and $M/P$ are Artinian modules, then $M/(N \cap P)$ is also Artinian. This conclusion is established through the properties of Artinian modules and the structure of submodules within a commutative ring $R$. The proof relies on the definitions and characteristics of Artinian modules, specifically their descending chain condition.

PREREQUISITES
  • Understanding of Artinian modules in the context of commutative algebra
  • Familiarity with submodules and quotient modules
  • Knowledge of the descending chain condition
  • Basic concepts of commutative rings and module theory
NEXT STEPS
  • Study the properties of Artinian modules in detail
  • Learn about the structure of submodules in commutative rings
  • Explore the implications of the descending chain condition in module theory
  • Investigate examples of Artinian modules and their applications
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Mathematicians, algebraists, and students studying module theory, particularly those interested in the properties of Artinian modules and their applications in commutative algebra.

Euge
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Here is this week's POTW:

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Let $R$ be a commutative ring. If $N$ and $P$ are submodules of an $R$-module $M$ such that $M/N$ and $M/P$ are Artinian, show that $M/(N\cap P)$ is Artinian.

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No one answered this week's problem. You can read my solution below.
$M/(N\cap P)$ is isomorphic to a submodule of the Artinian module $M/N \times M/P$ via the $R$-mapping $M/(N\cap P) \to M/N \times M/P$ given by $m + N\cap P \mapsto (m + N, m + P)$; hence, $M/(N\cap P)$ is Artinian.
 

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