Why is ∂μgλρ - ∂ρgμλ = 0 for the metric tensor?

felixphysics · May 27, 2013

[itex]\partial[/itex]_μg_λρ - [itex]\partial[/itex]_ρg_μλ = 0

I have reaced to this statement. Is this true? How?

What I thought is it looks like field strength tensor, but symmetric hence we can say it is true.

Thank you.

clamtrox · May 28, 2013

felixphysics said:

[itex]\partial[/itex]_μg_λρ - [itex]\partial[/itex]_ρg_μλ = 0

I have reaced to this statement. Is this true? How?

It's not generally true.

Why is ∂μgλρ - ∂ρgμλ = 0 for the metric tensor?

Discussion

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