Why is my frictional force calculation wrong for a crate on a 40° incline?

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lalahelp
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Homework Statement


A crate of potatoes of mass 13.0 kg is on a ramp with angle of incline 40° to the horizontal. The coefficients of friction are μs = 0.78 and μk = 0.43. Find the frictional force (magnitude) on the crate if the crate is at rest.



Homework Equations


F=ma
Ff=μmgcosα


The Attempt at a Solution



Ff=.78*13*9.81*cos40
=76.2 N


Why is my answer wrong?
 
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You assumed that the static friction would be equal to its maximum possible value (μN). Instead, solve for the value of static friction considering that the crate is in equilibrium.
 
lalahelp said:
what equation would i use to do that?
The net force is zero.
 
lalahelp said:
I don't understand it still
What forces act on the crate?
 
lalahelp said:
the mass and friction
The weight, the friction, and the normal force. What direction does each act?
 
the weights acts straight down, friction to the right, and normal force up
 
lalahelp said:
the weights acts straight down, friction to the right, and normal force up
Consider force components parallel to the incline and apply ΣF = 0.