Why Is My Integration Approach Not Working?

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SUMMARY

The forum discussion centers on the challenges faced in integrating a specific expression related to physics or engineering problems. The user struggles to transition from the expression "This expression may be written as..." to its integrated form. The correct integration involves recognizing the integration constant, which should be denoted by a different symbol to avoid confusion. The user is advised to evaluate the expression at t=0 to identify the initial condition, x_0, which clarifies the integration process.

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Homework Statement



http://i27.photobucket.com/albums/c171/Chewbacc0r/problem.jpg

The Attempt at a Solution



Basically, for the life of me I can't see how they get from "This expression may be written as..." to "Which may be integrated to contain..."

Now, I have no problem with the integration at all, I just can't see how they've put it in the right form.

Surely;

\frac{1}{v_{0}}+\frac{Ct}{m}= \frac{m+Ctv_{0}}{mv_{0}}

So (\frac{1}{v_{0}}+\frac{Ct}{m})^{-1}=\frac{mv_{0}}{m+Ctv_{0}}

Which integrates to;

\frac{m}{C}ln(m+Ctv_{0}) + C

However as you can see, this is apparently incorrect, and I have a feeling they're right. Just can't see where, I know I'm making a rookie mistake, but I've not practised math for months so it's quite frustrating.

Thanks in advance.

Edit:

I just thought - carrying on using my solution i could simply take \frac{m}{C}ln(m) away from both sides, changing the constant, however that feels like such a cop-out to me, though i guess it would work. I'd still like to know how they've done it if anyone knows.
 
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Chewy0087 said:
Surely;

\frac{1}{v_{0}}+\frac{Ct}{m}= \frac{m+Ctv_{0}}{mv_{0}}

So (\frac{1}{v_{0}}+\frac{Ct}{m})^{-1}=\frac{mv_{0}}{m+Ctv_{0}}

Which integrates to;

\frac{m}{C}ln(m+Ctv_{0}) + C

You've somehow identified the integration constant with C. Pick a different symbol and then evaluate the expression at t=0 to identify x_0.
 

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