Why Use a Weak Base to Neutralize a Strong Acid?

Click For Summary
SUMMARY

The discussion centers on the calculation of pH for a solution containing 0.050 moles of TRIS (RNH2) and 0.020 moles of HCl in a 2L volume. The correct pH calculation yields a final value of 8.26, derived from the pOH of 5.74 using the equation pOH = pKb + log([conjugate acid]/[base]). The conversation also explores the rationale behind using weak bases like calcium carbonate for neutralizing strong acids, emphasizing that the choice depends on the specific application and desired outcomes, such as buffering capacity.

PREREQUISITES
  • Understanding of acid-base chemistry, specifically weak bases and strong acids.
  • Familiarity with the Henderson-Hasselbalch equation for pH calculations.
  • Knowledge of TRIS (RNH2) and its conjugate acid (RNH3).
  • Basic principles of chemical reactions and equilibrium.
NEXT STEPS
  • Study the Henderson-Hasselbalch equation in detail for various buffer systems.
  • Learn about the properties and applications of calcium carbonate as a neutralizing agent.
  • Explore the concept of buffering capacity and its importance in chemical reactions.
  • Investigate the effects of different weak bases on pH levels in various solutions.
USEFUL FOR

Chemistry students, laboratory technicians, and professionals involved in chemical analysis or formulation who need to understand acid-base interactions and pH calculations.

enigmatic
Messages
8
Reaction score
0
Question: TRIS is a weak base. Compute pH of a solution containing .050 moles of TRIS and .020 moles of HCl in a total volume of 2L. pKb for TRIS is 5.92. Use RNH2 to represent TRIS.

Equation: pH = pKa+ log ([conjugate base]/[acid])

Work:
change equation for pOH:
pH = 14-pOH
pOH = pKb + log ([conjugate acid]/[base])
pOH = 5.02 + log (.010/.025) <---- I converted to mol/L for these values
pOH = 5.52
pH = 8.48

Real Answer: 8.26

Can someone show me where I went wrong? Thanks!
 
Physics news on Phys.org
What are your conjugated acid and base? What is your base concentration? (Hint: write reaction equation).

Borek
 
Last edited by a moderator:
They don't say what the conjugate acid and base is, except that the base is RNH2, so then its conjugate acid would be RNH3, right?

The base concentration would be .05/2 = .025 M.

The reaction equation would be
RNH2 + HCl <--> H2O + RNH3
Initial:
.25M .1M 0
Change:
-.1M -.1M .1M
Final:
.15M 0M .1M

pOH = pKb + log (.1/.15)
pOH = 5.92 + log (.1/.15)
pOH = 5.74
pH = 8.26

...

That's it! Thank you! :D :D
 
Why is it better to use a weak base(such as calcium carbonate) to neutralise strong acid (such as hcl) rather than strong base?

Thank you so much
 
Booo said:
Why is it better to use a weak base(such as calcium carbonate) to neutralise strong acid (such as hcl) rather than strong base?

Thank you so much

Generally, a weak base is not better and not worse. The choice depends on the application. Why do you ask?

If you use calcium carbonate to neutralize a strong acid, you hopefully are not worried about the presence of calcium, and the resulting carbon dioxide may be mostly insoluble, but beware of bubbling or foaming. Depending on quantities involved of the base(calcium carbonate) and the acid, you might be choosing to produce a buffer; is that what you wanted? Did you want some bicarbonate present?
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 22 ·
Replies
22
Views
7K
  • · Replies 7 ·
Replies
7
Views
7K