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I apologize in advance if the answer to this is really simple; I often overlook simple solutions when something trips me up.
For example, if f(x)=x^{2} and g(x)=x^{3/2}, and g(f(x)) is therefore, after simplification, x^{3}, why is that still an even function if x^{3} graphed under other circumstances is odd?
For example, if f(x)=x^{2} and g(x)=x^{3/2}, and g(f(x)) is therefore, after simplification, x^{3}, why is that still an even function if x^{3} graphed under other circumstances is odd?