- #1
robertmatthew
- 48
- 0
I apologize in advance if the answer to this is really simple; I often overlook simple solutions when something trips me up.
For example, if f(x)=x2 and g(x)=x3/2, and g(f(x)) is therefore, after simplification, x3, why is that still an even function if x3 graphed under other circumstances is odd?
For example, if f(x)=x2 and g(x)=x3/2, and g(f(x)) is therefore, after simplification, x3, why is that still an even function if x3 graphed under other circumstances is odd?