Will the Block Move and What is Its Acceleration?

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SUMMARY

A block weighing 35.0 N is subjected to a horizontal force of 41 N on a table, with static and kinetic friction coefficients of 0.650 and 0.420, respectively. The applied force exceeds the maximum static friction force, calculated as 22.75 N (35.0 N * 0.650), indicating that the block will move. Once in motion, the block experiences kinetic friction, resulting in an acceleration of 0.57 m/s², derived from the net force of 18.25 N (41 N - 22.75 N) divided by the block's mass (approximately 3.57 kg).

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A block whose weight is 35.0 N rests on a horizontal table. A horizontal force of 41 N is applied to the block. The coefficients of static and kinetic friction are 0.650 and 0.420 N, respectively. Will the block move under the influence of the force, and, if so, what will be the block's acceleration?

m/s^2= ?
 
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vntraderus said:
A block whose weight is 35.0 N rests on a horizontal table. A horizontal force of 41 N is applied to the block. The coefficients of static and kinetic friction are 0.650 and 0.420 N, respectively. Will the block move under the influence of the force, and, if so, what will be the block's acceleration?

m/s^2= ?

Do you want someone here to replace the question mark with an answer, or do you want to know what m/s2 means?

I should point out that PF rules state that we must see some work from you, and we will not give out final solutions to homework problems.

So, what work have you done so far?
 

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