Word problem for a bus travel and a boat accelerating

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Hey everybody, I need help on a few word problems. The major problem I'm having is finding a formula to use.

A bus is going to a football game and leaves at 4:00pm. It travels 20.91 miles to the game in 33 minutes. What is the bus' average speed in miles per hour?

I'm completely clueless on this.

How man seconds would it take a boat to accelerate from 13 m/s to 26 m/s over a distance of 1.25 km?

For this problem I'm using the average acceleration formula, but i'm not getting the answer my teacher got.

Thanks for your help!
 

Answers and Replies

  • #2
berkeman
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Hey everybody, I need help on a few word problems. The major problem I'm having is finding a formula to use.

A bus is going to a football game and leaves at 4:00pm. It travels 20.91 miles to the game in 33 minutes. What is the bus' average speed in miles per hour?

I'm completely clueless on this.

How man seconds would it take a boat to accelerate from 13 m/s to 26 m/s over a distance of 1.25 km?

For this problem I'm using the average acceleration formula, but i'm not getting the answer my teacher got.

Thanks for your help!
a) What is the average speed in miles per minute? How many minutes in an hour?

b) Show us your work on this, so we can see if we see the error.
 
  • #3
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a) What is the average speed in miles per minute? How many minutes in an hour?

b) Show us your work on this, so we can see if we see the error.
The mile per minute is .633 and there are 60 minutes in an hour. Sorry, but I still can't find a formula for this.

For the boat my givens are:
Vi = 8.0 m/s
a = 10.0 m/s
dt = 5s

I used the formula of dx = 1/2(vi+a)dt

dx = 1/2(8+10)(5)
dx = 8(5)
dx = 40
 
  • #4
berkeman
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58,776
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The mile per minute is .633 and there are 60 minutes in an hour. Sorry, but I still can't find a formula for this.
You don't need a formula. Just "multiply by 1" to convert units:

https://www.physicsforums.com/showthread.php?t=425866&highlight=conversion


For the boat my givens are:
Vi = 8.0 m/s
a = 10.0 m/s
dt = 5s

I used the formula of dx = 1/2(vi+a)dt

dx = 1/2(8+10)(5)
dx = 8(5)
dx = 40
I think you are looking at a different problem now. Above, you said this for the 2nd problem:

How man seconds would it take a boat to accelerate from 13 m/s to 26 m/s over a distance of 1.25 km?
 
  • #6
berkeman
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58,776
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Cool. Glad you t\figured them out.

Welcome to the PF!
 

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