Work and spring constant questions?

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Homework Help Overview

The discussion revolves around two physics problems: one involving work done in lifting a mass and the other concerning Hooke's law and spring constants. The first problem asks for the depth of a well when a bucket is lifted, while the second problem explores the behavior of a spring under different forces.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the work formula and the force of gravity in the first problem, questioning the calculations and assumptions made. In the second problem, there is uncertainty about how to begin solving for the spring constant and the length of the spring under tension.

Discussion Status

Some participants have provided hints and guidance regarding the correct approach to calculating force and work. There is an ongoing exploration of the equations relevant to both problems, with multiple interpretations being considered.

Contextual Notes

Participants note that the original poster has encountered difficulties with the homework, and there is a mention of a potential error in the provided answers from a website. The discussion reflects a learning process rather than a resolution of the problems.

bbanas0695
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1) If a man lifts a 11.0 kg bucket from a well and does 7.00 kJ of work, how deep is the well? Assume that the speed of the bucket remains constant as it is lifted.

2) Hooke's law describes a certain light spring of unstretched length 36.0 cm. When one end is attached to the top of a door frame, and a 7.60-kg object is hung from the other end, the length of the spring is 45.50 cm.

(a) Find its spring constant.
(b) The load and the spring are taken down. Two people pull in opposite directions on the ends of the spring, each with a force of 170 N. Find the length of the spring in this situation.

work=fd
PE=(1/2)k(x^2)

ok for the first one i did 7000J/11= 636.36 and it says that's wrong
and for the second one I am not even sure where to start
 
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bbanas0695 said:
1) If a man lifts a 11.0 kg bucket from a well and does 7.00 kJ of work, how deep is the well? Assume that the speed of the bucket remains constant as it is lifted.

work=fd


ok for the first one i did 7000J/11= 636.36 and it says that's wrong

You are using the correct equation, work = fd. So, what is f, the force required to lift a mass of 11 kg? Hint: it is the same as the force of gravity exerted on the mass.

2) Hooke's law describes a certain light spring of unstretched length 36.0 cm. When one end is attached to the top of a door frame, and a 7.60-kg object is hung from the other end, the length of the spring is 45.50 cm.

(a) Find its spring constant.
(b) The load and the spring are taken down. Two people pull in opposite directions on the ends of the spring, each with a force of 170 N. Find the length of the spring in this situation.


PE=(1/2)k(x^2)
There is another useful equation for springs, relating force and displacement (amount of stretch) of the end of the spring. Find that equation and try to apply it here.
 
You are using the correct equation, work = fd. So, what is f, the force required to lift a mass of 11 kg? Hint: it is the same as the force of gravity exerted on the mass.

the force of gravity is 9.81 so that would be the force. so 7000/9.81= 713.56 m ?

and for the second one, i guess we don't have to do it. the answer in the website is wrong or something.
 
oh wait. you need to find force using f=ma so 11*9.81=107.91
and then plug that in which would be 7000/107.91= 64.87m
i already got it wrong on the homework but thanks. At least I know how to do it now :)
 
bbanas0695 said:
oh wait. you need to find force using f=ma so 11*9.81=107.91
and then plug that in which would be 7000/107.91= 64.87m
i already got it wrong on the homework but thanks. At least I know how to do it now :)
Looks good. Too late for the homework, but remember it for the test :smile:
 

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