Work done when a car accelerates from 26.5m/s to 30m/s

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Veronica_Oles
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Homework Statement


calculate work when mass of car is 2400kg and displacement is 200m the car travels at velocity of 26.5m/s then speeds up to 30m/s

Homework Equations


M- 2400 kg
Vi - 26.5m/s
Vf- 30 m/s
D- 200 m

The Attempt at a Solution


I am struggling with figuring out how to solve this problem would i have to use the formula w = Ek - Ek? But theb i don't end up usinh displacement is there no need to use it here? Does the question have too much information given?
 
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Veronica_Oles said:
Does the question have too much information given?
What do you think and why?
 
There are two ways to solve the problem and both give the same answer.
 
Orodruin said:
What do you think and why?
I think that yes u can solve without displacement. Thats the way i make sense of the question Ek final minus Ek initial!
 
Veronica_Oles said:

Homework Statement


calculate work when mass of car is 2400kg and displacement is 200m the car travels at velocity of 26.5m/s then speeds up to 30m/s

Homework Equations


M- 2400 kg
Vi - 26.5m/s
Vf- 30 m/s
D- 200 m

The Attempt at a Solution


I am struggling with figuring out how to solve this problem would i have to use the formula w = Ek - Ek? But theb i don't end up usinh displacement is there no need to use it here? Does the question have too much information given?

use ##W = {1\over 2}m(v_f^2 - v_i^2)##
 
You can also solve it by using the displacement and the equations of motion to calculate the acceleration. Then apply Newtons law to give the force. Then work = force * distance. Gives same answer as calculating the change in KE.
 
Veronica_Oles said:
But theb i don't end up usinh displacement is there no need to use it here?
Have you quoted the whole question, word for word? It reads a bit strangely.
If so then I applaud the question setter. It should happen much more often that questions include redundant information. Figuring out which information is useful is a necessary skill in the real world.