Working out the intercept of the Y-Axis

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SUMMARY

The discussion centers on calculating the Y-intercept of a line given a gradient of -578.947 and a coordinate point of (0.00000227, 0.00100). The equation of a line is defined as y = ax + b, where 'a' represents the gradient and 'b' is the Y-intercept. By substituting the given coordinate into the equation, the Y-intercept can be determined using the formula y = y_0 - mx_0, resulting in the calculation of the intercept based on the provided values.

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  • Familiarity with coordinate geometry
  • Basic algebraic manipulation skills
  • Knowledge of how to interpret gradient values
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  • Study the derivation of the slope-intercept form of a line
  • Learn how to calculate Y-intercepts from different coordinate points
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If a gradient of -578.947 is present on a line of best fit then how can you work out the intercept of the Y-Axis when a co-ord of:

(0.00000227, 0.00100) is given?

Thank you
 
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Dearster said:
If a gradient of -578.947 is present on a line of best fit then how can you work out the intercept of the Y-Axis when a co-ord of:

(0.00000227, 0.00100) is given?

Thank you

Well, a line is usually given by the equation y=ax+b, and the y-intercept i.e, the value of y when x=0 is evidently y=b.

Having given coordinates (X,Y) of some point, you know that:

Y=aX+b. Determine what a and b is from this.
 
A line with slope m, passing through [itex](x_0,y_0)[/itex] has equation [itex]y= m(x-x_0)+ y_0[/itex]. Put x= 0 and you have [itex]y= y_0- mx_0[/itex].
 

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