Writing PDEs as differential equations on Hilbert space

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agahlawa
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Hi,

I was reading a paper on control of the 1-D heat equation with boundary control, the equation being
[itex]\frac{\partial u(x,t)}{\partial x}[/itex]= [itex]\frac{\partial^2 u(x,t)}{\partial x^2}[/itex] with boundary conditions:

[itex]u(0,t)=0[/itex] and [itex]u_x(1,t)=w(t)[/itex], where [itex]w(t)[/itex] is the control input.

The authors then proceed to write the equation as:

[itex]v(t)=Av(t)+\delta_1(x)w(t)[/itex] where [itex]A[/itex] is the double differential operator, [itex]v(t)=u(\cdot,t)[/itex] is the state with [itex]L_2(0,1)[/itex] being the state space and [itex]\delta_1[/itex] being the dirac delta distribution centered at [itex]x=1[/itex].

I understand the idea behind putting [itex]A[/itex] but I do not understand how the two equations are same.

Any help is much appreciated.
Thanks.
 
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agahlawa said:
Hi,

[itex]\frac{\partial u(x,t)}{\partial x}[/itex]= [itex]\frac{\partial^2 u(x,t)}{\partial x^2}[/itex]
Any help is much appreciated.
Thanks.

For a diffusion equation, the first derivative is wrt to time.
[tex]\frac{\partial u(x,t)}{\partial t}= \frac{\partial^2 u(x,t)}{\partial x^2}[/tex]
 
agahlawa said:
Hi,

I was reading a paper on control of the 1-D heat equation with boundary control, the equation being
[itex]\frac{\partial u(x,t)}{\partial t}[/itex]= [itex]\frac{\partial^2 u(x,t)}{\partial x^2}[/itex] with boundary conditions:

[itex]u(0,t)=0[/itex] and [itex]u_x(1,t)=w(t)[/itex], where [itex]w(t)[/itex] is the control input.

The authors then proceed to write the equation as:

[itex]v(t)=Av(t)+\delta_1(x)w(t)[/itex] where [itex]A[/itex] is the double differential operator, [itex]v(t)=u(\cdot,t)[/itex] is the state with [itex]L_2(0,1)[/itex] being the state space and [itex]\delta_1[/itex] being the dirac delta distribution centered at [itex]x=1[/itex].

I understand the idea behind putting [itex]A[/itex] but I do not understand how the two equations are same.

Any help is much appreciated.
Thanks.

Sorry, was a typo. Fixed. Thank you.