Writing Product States: When to Use a Sum?

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Discussion Overview

The discussion revolves around the conditions under which a quantum state can be expressed as a product state for two systems versus when a sum of product states is necessary. Participants explore the implications of these representations in the context of entanglement and quantum state evolution.

Discussion Character

  • Debate/contested
  • Conceptual clarification
  • Technical explanation

Main Points Raised

  • Some participants propose that the quantum state of a whole system is generally a sum of product states for two subsystems, but it can sometimes be factorized into a product of states.
  • It is suggested that depending on the Hamiltonian, a product of quantum states may evolve into an entangled state over time.
  • One participant questions the correct terminology for combining states, indicating uncertainty about the use of "tensor" versus other terms.
  • There is a discussion about whether a sum of product states necessarily indicates entanglement, with some arguing that it can be factored into a product state without entanglement.
  • Another participant references Erich Joos, suggesting that a sum of product terms implies entanglement, which leads to further clarification about the conditions under which entanglement arises.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between sums of product states and entanglement, with some asserting that a sum indicates entanglement while others argue that it does not necessarily imply entanglement if it can still be factored.

Contextual Notes

There are unresolved questions regarding the definitions and conditions under which states are considered entangled or separable, as well as the implications of Hamiltonians on state evolution.

StevieTNZ
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How do we know when we can write a product state for two systems, and situations when you need to use a sum of product states?

If you have a product state for two systems, does it evolve into a sum?
 
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In general, the quantum state of the whole system is a sum of product states for the two (disjoint) subsystems, but often this quantum state can be factorized into a product of states for the two subsystems. And yes, depending on the Hamiltonian it is in principle possible for a product of quantum states to evolve in time into an entangled state, but usually the Hamiltonian is nicer than that.
 
Okay so if we have two pairs of entangled photons:
We'd write the whole state of both pairs as the sum of the product state (which would be two photons TENSOR two photons)?

I don't even know if tensor is the right word (circle with x in it?)?
 
StevieTNZ said:
Okay so if we have two pairs of entangled photons:
We'd write the whole state of both pairs as the sum of the product state (which would be two photons TENSOR two photons)?

I don't even know if tensor is the right word (circle with x in it?)?
Yes, exactly. And that symbol is a tensor product.

If you want to see this all done in detail, you can read Sakurai, the standard graduate text on QM. Or at an undergraduate level Townsend does a good job of covering this ground, and it's relatively short.
 
And when we write a sum of product states, they're entangled?
 
StevieTNZ said:
And when we write a sum of product states, they're entangled?
If we write a quantum state as a sum of products of arbitrary states (they could be linearly dependent, for instance), then we may still be able to factor this state as a product of states, so there's not entanglement. If, however, it cannot be factored into a single product, then it's entangled.
 
Now I'm confused, because Erich Joos is saying "When you have to use a sum of product terms, you have an entangled state"
 
StevieTNZ said:
Now I'm confused, because Erich Joos is saying "When you have to use a sum of product terms, you have an entangled state"
That's the point, when you have to use a sum, then it's entanglement. But if it's merely possible to write it using a sum, that need not be entanglement.
 
Ah yes. That makes more sense. Thanks for pointing that out!
 

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