Does the KE Equation Apply in Relativistic Scenarios?

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SUMMARY

The kinetic energy (KE) equation does not apply in relativistic scenarios. Instead, the relativistic kinetic energy is derived from the equations of relativistic kinetic energy and momentum. The correct formula for relativistic kinetic energy is K = (m₀c² / √(1 - v²/c²)) - m₀c², while momentum is expressed as p = (m₀v / √(1 - v²/c²)). Additionally, the relationship between total energy, mass, and momentum is defined by E² = (pc)² + (m₀c²)², which can be manipulated to find kinetic energy.

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sweetvirgogirl
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refer to the title.

I'm confused whether this eqn works in relativistic situations?

thanks in advance
 
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No, that equation does not work in relativistic situations. To get the corresponding relativistic equation, take the equations for relativistic kinetic energy and momentum and eliminate v between them:

[tex]K = \frac{m_0 c^2}{\sqrt{1 - v^2 / c^2}} - m_0 c^2[/tex]

[tex]p = \frac{m_0 v}{\sqrt{1 - v^2 / c^2}}[/tex]

Or, you can take the relativistic relationship between total energy, mass and momentum:

[tex]E^2 = (pc)^2 + (m_0 c^2)^2[/tex]

substitute [itex]E = m_0 c^2 + K[/itex] (total energy equals rest energy plus kinetic energy), and solve for K.
 
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