Coloumbs Laws and electric fields

[SS2006]

Determine the acceleration of a proton (q = +e, m = 1.67 E -27)
in an electric field of intensity 500 N/C. How many times is this acceleration greater then that due of gravity

I'm not so understanding on todays lessons
teh 2 formulas I can recall are f = q*e
and e = f/q
but i dont see that helping here, can someone help me start off
thanks guys.

[Tide]

HINT: Force = mass x acceleration

[SS2006]

yup i knew of that
i got mass, im looking for acceleration
but whats force
f = q * e right
i got e just dont know what q is (what they mean by q = +e)

[cwire4]

http://hyperphysics.phy-astr.gsu.edu/hbase/tables/funcon.html

Useful little table there of constants, e is the charge of an electron.

[SS2006]

oh roger that
thanks