A sound problem

[Moe_slow]

i need some help with this question.

"Jim is walking in a field and screams...the wall is 300 meters away it takes 1.7 seconds for the sound to come back.......wat is the temperature in the air."

so i tried it as:

V=d/t
....= 300m/0.85s
....= 353m/s

from there i think i have to use the speed of sound formula and isolate the 0.59t. and then divide by it. i keep on getting a different answer then the one in my textbook.

[PPonte]

Cair= 331.5 + (0.6 x theta)
353 = 331.5 + (0.6 x theta)
theta = (353 - 331.5)/0.6
theta = 35.8 ºC

It's hot!
Notice that I get this formula from wikipedia, I could be wrong since I never learned this. But I read the article and it seems to be correct.

See- http://en.wikipedia.org/wiki/Speed_of_sound

[Moe_slow]

thanks its correct...