PDA

View Full Version : constant vector?


jlmac2001
Jan29-04, 06:15 PM
Okay, here's the question:

For r=xi + yj +zk evaluate grad x (k x r), where k is a constant vector.

I know how to do the cross product of k x r and I know how to do
grad x (k x r). But I don't know what k is. What's k?

Doc Al
Jan29-04, 06:59 PM
Originally posted by jlmac2001
... But I don't know what k is. What's k?
Try assuming an arbitrary k vector: ai + bj + ck (or whatever). Then see what happens.

jlmac2001
Jan29-04, 07:52 PM
The answer I got is: -2ai-2bj-2ck

Doc Al
Jan29-04, 08:06 PM
Originally posted by jlmac2001
The answer I got is: -2ai-2bj-2ck
I got 2k (where k is the constant vector) but I did it quick. (So my answer differs by a minus sign from yours.) My main point was that you didn't have to know the value of k (the a, b, & c) to do the problem.

jlmac2001
Jan29-04, 08:16 PM
how did you just get 2k? i don't understand

Doc Al
Jan29-04, 08:26 PM
Originally posted by jlmac2001
how did you just get 2k? i don't understand
By "2k" I mean: 2ai + 2bj + 2ck. (The same as you, but with a + instead of -.) 2\vec{k} is what I should have written. Make sense?

jlmac2001
Jan29-04, 09:01 PM
i get it now