View Full Version : electric field
pringless
Feb4-04, 06:13 PM
The electron gun in a televeision tube is used to accelerate electrons (mass of 9.10939 x 10^-31 kg and charge of -1.60218 x 10^-19 C) from rest to 2 x 10^7 m/s within a distance of .053 m. What electric field is required?
The question only looks complicated because of the big (or small) numbers. You are given a change in velocity, a distance, and a charge.
First find the acceleration on the electron with this equation.
V_f^2 = V_i^2 + 2ad
Now find the force on the electron with this equation
F = ma
Now find the electric field with this equation
E = \frac{F}{q}
vBulletin® v3.8.7, Copyright ©2000-2012, vBulletin Solutions, Inc.