View Full Version : Parallel of Least Radius
Dragonfall
Mar13-07, 08:52 PM
1. The problem statement, all variables and given/known data
Show that on of the hyperboloid of revolution x^2+y^2-z^2=1, the parallel of least radius is the line of striction, ...
What's the parallel of least radius?
HallsofIvy
Mar14-07, 06:33 AM
The "parallel of least radius" is the line, parallel to an axis, that is shortest from one point on the hyperboloid to another.
Now, clear up my confusion: what is a "line of striction"?
Dragonfall
Mar14-07, 06:42 AM
Given a ruled surface x(t,v)=a(t)+vw(t), a line of striction is a curve b(t) such that <b'(t),w'(t)>=0 for all t and b lies on the trace of x, ie b(t)=a(t)+u(t)w(t) for some real valued function u(t). It be can then shown that u(t) is given by
u=-\frac{<a',w'>}{<w',w>}.
The points of a line of striction are the "central points" of the ruled surface.
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