Drinking cup

[Winzer]

1. The problem statement, all variables and given/known data
A cone-shape drinking cup is made from a circular piece of paper of radius R by cutting out a sector and joining the edges CA and CB. Find the maximum capacityof such a cup. This is page#312 In James stewarts Calc book, 3rd edition by the way.

2. Relevant equations
V=\frac{1}{3}\pi r^2 h

3. The attempt at a solution
So realize this will form a cone with an inner triangle of hypotnue R. The base will have a radius r and a hieght h. So I will have to make a relationship between r and h to get R to plug into V=\frac{1}{3}\pi h r^2 and differeniate?

[Dick]

(1/3)*pi*r^2 doesn't even have the units of a volume. (1/3)*pi*r^2*h does. I think that's what you want. You will want to parametrize r and h by the angle cut out of R. And then differentiate and maximize wrt to the angle.

[Winzer]

sorry clumsy mistake, I forgot the H, lol.

[Dick]

sorry clumsy mistake, I forgot the H, lol.

I thought so. But just write r and h as functions of the cut out angle. That's just geometry.

[HallsofIvy]

Notice that the entire circle of paper has circumference 2\pi R but the circle at the top of the cone has circumference 2\pi r. The arc length of the cut out wedge is R \theta/\2\pi where \theta is the angle in radians. That must be the difference between 2\pi R and 2\pi r.

[Winzer]

mmmm.......

[Dick]

Ok, then let's try it another way. Draw the right triangle joining a point on the circle of the base of the cone to the apex of the cone. Height is h and base is r, right? What's the length of the hypotenuse? Use Pythagoras to eliminate one of the variables (r or h) from the formula for the volume and maximize.