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philipc
Apr18-04, 12:01 AM
I'm kind of stuck with the xf(0), hope this is the right place for this question?

let L(f) = 2Df - xf(0)
is L a linear transformation on the space of differentiable functions?

thanks for your help
Philip

chroot
Apr18-04, 12:34 AM
I'm guessing that x is just some constant, in which case xf(0) is also just some constant. If so, it doesn't affect the linearity of the entire function.

- Warren

philipc
Apr18-04, 12:48 AM
Thanks, I didn't think of it like that,
Philip

Hurkyl
Apr18-04, 11:44 AM
The other possibility is that it's supposed to be written as:

L(f)(x) = 2(Df)(x) - x f(0)

so the x is not a constant.

Max0526
Apr18-04, 12:21 PM
But nevertheless it's still linear in f.
Max.