View Full Version : Squeeze theorem
fr33pl4gu3
Aug23-08, 04:11 PM
f(x)=x4 cos(2/x6)
g(x) <= f(x) <= h(x)
how to get g(x) and h(x) by using the squeeze theorem??
I know is something like this -1 <= x <= 1
But how do i implement it here, and especially to the cos, sin, and tan??
fr33pl4gu3
Aug23-08, 04:14 PM
solve the problem!!
So in your question, x^4 . cos \frac{2}{x^6} what's the limit ie. as x approaches what? zero?
Then we can use the squeezing theorem; g(x) \leq f(x) \leq h(x)
Assuming that the limit of f(x) as x approaches c is L then;
lim_{x \rightarrow c} g(x) = lim_{x\rightarrowc} h(x) = L
Thus lim_{x \rightarrow c} f(x) = L
HallsofIvy
Aug23-08, 06:16 PM
What exactly is the question? The "squeeze theorem" refers to limits but you are trying to find the limit of x4cos(2/x6) as x goes to what?
(And it is your responsibility to "solve the problem"!)
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