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circuits
Jason03
Sep4-08, 05:22 PM
I was looking to an approach for this problem below....
http://img389.imageshack.us/img389/9387/screenshot003yw2.png
CEL
Sep4-08, 05:39 PM
Use superposition.
With the dc source, the inductor is a short circuit and the capacitor is an open circuit.
With the ac source the inductor impedance is j\omega L and the capacitor impedance is \frac{1}{j\omegaC}.
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