Does anyone know if there is a relation between a materials capacitance (C) and its dielectric constant (K)?
Thanks,
Apteronotus
Sep28-08, 12:03 PM
So I think I may have figured it out, and for people reading the post here is my attempt at the answer:
K_{e}=1+\chi_{e}=1+\frac{\epsilon-\epsilon_{0}}{\epsilon_{0}}=1+\frac{\epsilon_{r}\epsilon_{0}-\epsilon_{0}}{\epsilon_{0}}=1+\epsilon_{r}-1=\epsilon_{r}
\epsilon_{r}=\frac{C_{x}}{C_{0}}
So
K_{e}=\frac{C_{x}}{C_{0}}
where
K_{e} - dielectric constant
\chi_{e} - electric susceptibility
\epsilon - permittivity of the dielectric material
\epsilon_{r} - relative permittivity
\epsilon_{0} - permittivity of free space
C_{x} - capacitance of the dielectric material
C_{0} - capacitance of vacuum