Mandl and Shaw, page 16, eqn (1.56)

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SUMMARY

The discussion centers on the equation from Mandl and Shaw, specifically equation (1.56), which relates the electric field \( E_L \) to the potential \( \phi \) through the charge distribution \( \rho \). The integral \( \int E_L^2 d^3x \) is evaluated using the relationship \( E_L = -\nabla\phi \) and the Poisson equation \( \nabla^2\phi = -\rho \). The solution involves recognizing that \( \phi(x) \) can be expressed as \( \phi(x) = \int \frac{\rho(x') d^3x'}{4\pi|x - x'|} \), confirming the connection between the potential and charge distribution in electromagnetism.

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This discussion is beneficial for physics students, particularly those studying electromagnetism, as well as educators and researchers looking to deepen their understanding of electric fields and potentials in theoretical contexts.

Jimmy Snyder
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Homework Statement


[tex]\int{E}_L^2d^3x = \int\frac{\rho(x)\rho(x')}{4\pi|x - x'|}d^3xd^3x'[/tex]

Homework Equations


[tex]{E}_L = -\nabla\phi[/tex]
[tex]{\nabla}^2\phi = -\rho[/tex]


The Attempt at a Solution


[tex]\int{E}_L^2d^3x = \int(\nabla\phi)^2d^3x = -\int\phi\nabla^2\phi d^3x = \int\rho(x)\phi(x)d^3x[/tex]
I suppose to finish up, I need to see why
[tex]\phi(x) = \int\frac{\rho(x')d^3x'}{4\pi|x - x'|}[/tex]
But I don't see it. Or am I on the wrong track.

By the way, I have the 1993 revised edition.
 
Last edited:
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Thanks malawi_glenn, that's what I needed.
 

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