View Full Version : Rearranging equation vČ=uČ+2as
Infamous
Mar4-09, 04:19 AM
I have been trying but i cant quite figure out how to rearrange this so that 's' (displacement) is the subject. Please help me figure this out.
Sorry if this is in the wrong place.
What have you gotten so far?
Start by isolating "2as" to one side.
Infamous
Mar4-09, 05:25 AM
Mostly what i had tried involved me immediately trying move 's' to the other side (so eg. vČ/s=uČ+2a), which hadnt been working for me. So, by isolating 2as, would this be correct as what i end up with:
vČ-uČ
_____ = s ?
2a
(Ordinarily 's' would be on the other side, but i couldn't work out how to do fractions on this forum).
So, is that pretty much right?
Yep, you got it. :biggrin:
(Ordinarily 's' would be on the other side, but i couldn't work out how to do fractions on this forum)
You can use Latex for it on the advanced posting screen, the button(\Sigma) is on the upper right:
s = \frac{v^2-u^2}{2a}
Infamous
Mar4-09, 06:20 AM
Awesome, now that I understand this the rest of my work is easy. Thanks!
You can use Latex for it on the advanced posting screen, the button(\Sigma) is on the upper right:
s = \frac{v^2-u^2}{2a}
Thanks for telling me about this, many forums i visit I've needed something like this, but never known how to use it.
Awesome, now that I understand this the rest of my work is easy. Thanks!
Thanks for telling me about this, many forums i visit I've needed something like this, but never known how to use it.
No problem, just take a little bit to get used to. I'm still trying to figure it out too. :yuck:
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