PDA

View Full Version : How is 3D d-wave superconductivity band?


MTd2
Sep24-09, 10:58 AM
Please,

I found this (the 4 lobe object in the center):
http://www.physics.utoronto.ca/lecture-and-seminar-series/colloquium/events/tsuei.jpg

But is it the same throughout the z axis, or does it vary significantly?

genneth
Sep25-09, 05:09 AM
I assume this is a description of the d-wave superconductivity as found in the cuprates. In those materials, there is a very prominent layered structure. So yes, along the z-axis the pairing function is constant. Remember however that you're looking at the pairing function in the momentum/Fourier-transformed space.

ZapperZ
Sep25-09, 06:23 AM
Or to be more specific, it is the d_{x^2-y^2} symmetry. So if you open any atomic spectroscopy book, look up that orbital symmetry and there you have it.

Zz.

genneth
Sep25-09, 07:31 AM
Or to be more specific, it is the d_{x^2-y^2} symmetry. So if you open any atomic spectroscopy book, look up that orbital symmetry and there you have it.

Zz.

Though atomic orbitals are spherical harmonics, so have a slightly different z-axis symmetry. In this case, the "lobes" should be open, so that concatenating Brilliouin zones creates a sort of "sausage". Otherwise, yes, it's called d_{x^2-y^2}, but only because its x-y plane symmetry has the same nodes (I'd like to say the same shape in general, but am not sure?)