View Full Version : Determing speed of water
Beastegargoyl
Nov29-09, 11:31 AM
1. The problem statement, all variables and given/known data
River Pascal with a volume flow rate of 4.7×105 joins with River Archimedes, which carries 1.1×106 , to form the Bernoulli River. The Bernoulli River is 130 wide and 30 deep.
What is the speed of the water in the Bernoulli River?
2. Relevant equations
Express your answer using two significant figures.
3. The attempt at a solution
I attempted to guesses so far.
0.120 m/s was wrong
1.20 m/s was wrong
Thanks for all the help.
Jared
tiny-tim
Nov29-09, 03:39 PM
Hi Jared! Welcome to PF! :smile:
(try using the X2 tag just above the Reply box :wink:)
River Pascal with a volume flow rate of 4.7×105 joins with River Archimedes, which carries 1.1×106 , to form the Bernoulli River. The Bernoulli River is 130 wide and 30 deep.
What is the speed of the water in the Bernoulli River?
…
I attempted to guesses so far.
0.120 m/s was wrong
1.20 m/s was wrong
Show us your full calculations, and then we can see what went wrong, and we'll know to help! :smile:
Beastegargoyl
Nov29-09, 06:30 PM
For vfr=4.7*105L/s
I used the equation 4.7*105/3900 equals 1.2m/s
Thanks for the help.
Jared
tiny-tim
Nov30-09, 02:55 AM
Hi Jared! :smile:
(just got up :zzz: …)
River Pascal with a volume flow rate of 4.7×105 joins with River Archimedes, which carries 1.1×106 , to form the Bernoulli River. The Bernoulli River is 130 wide and 30 deep.
What is the speed of the water in the Bernoulli River?
For vfr=4.7*105L/s
I used the equation 4.7*105/3900 equals 1.2m/s
oh i see … you only used the volume flow rate of River Pascal.
The Bernoulli River contains the water of both River Pascal and River Archimedes. :wink:
Beastegargoyl
Nov30-09, 01:19 PM
@tiny-tim- Did you come up with an answer of .40m/s where that incportates both rivers?
Thanks for your help,
Jared
tiny-tim
Nov30-09, 01:56 PM
@tiny-tim- Did you come up with an answer of .40m/s where that incportates both rivers?
I go 4.0 times something …
what are the units of the problem? :confused:
Beastegargoyl
Nov30-09, 02:15 PM
4.7*105L/s and 1.1*106L/s. 130m wide and 30m deep.
The answer needs to be expressed in m/s.
tiny-tim
Nov30-09, 03:09 PM
4.7*105L/s and 1.1*106L/s. 130m wide and 30m deep.
The answer needs to be expressed in m/s.
oh, litres! :rolleyes:
ok, then i make it .40m/s :smile:
vBulletin® v3.8.7, Copyright ©2000-2012, vBulletin Solutions, Inc.