Entropy Question: Calculating Entropy Change for a Diamond

  • Thread starter Thread starter Jerzey2Atl
  • Start date Start date
  • Tags Tags
    Entropy
Click For Summary
SUMMARY

The discussion focuses on calculating the entropy change of a diamond when heated from 10.0 K to 350 K using Debye's law. The molar heat capacity at constant volume for diamond is given by the equation Cv = (12*pi^4*R / 5) x (T / TD)^3, where TD is 2230 K. The user seeks guidance on applying the entropy equation ΔS = ∫(T1 to T2) Cv (dT/T) and emphasizes the need to calculate the molar mass of carbon, which is 12.0 g/mol, to determine the number of moles for the calculation.

PREREQUISITES
  • Understanding of Debye's law and its application to heat capacity
  • Familiarity with the concept of entropy in thermodynamics
  • Knowledge of integral calculus for evaluating the entropy change equation
  • Basic understanding of molar mass and its significance in thermodynamic calculations
NEXT STEPS
  • Study the derivation and implications of Debye's law for different materials
  • Learn how to apply the entropy change equation in various thermodynamic scenarios
  • Explore the relationship between temperature, heat capacity, and entropy in solid-state physics
  • Investigate the significance of molar mass in thermodynamic calculations and its impact on entropy
USEFUL FOR

This discussion is beneficial for students and professionals in thermodynamics, particularly those studying solid-state physics, as well as anyone involved in calculating entropy changes in materials like diamond.

Jerzey2Atl
Messages
3
Reaction score
0
Hi, this is my first time using this forum. I have a question dealing with entropy and thermodynamics.

Here goes:

According to Debye’s law, the molar heat capacity at constant volume of a
diamond varies with temperature according to the relation

Cv = (12*pi^4*R / 5) x (T / TD)^3

where TD = 2230 K. For a diamond of mass 1. 20 g, what is its entropy change when it is heatedat constant volume from 10. 0 K to 350 K? The molar mass of carbon is 12. 0 g/mol.

I know Ih ave to first find the molar mass, but I am not sure of which form of the entropy equation to use. Any help is appreciated.
 
Physics news on Phys.org
To solve the problem you can use this equation to find the molar entropy

[tex]\Delta S = \int_{T_1}^{T_2} C_v \frac{dT}{T}[/tex]

Multiply this result by the numer of moles (1.2/12) to get entropy in terms of energy/time.
 
Thanks a lot...imma try this.
 

Similar threads

  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K