View Full Version : A problem in polar i want check my answer
write in polar form ...elc
-3 - 5i
my answer :
x = -3 y = - 5
r = root (-3)^2 + (-5)^2
= 5.83
tan Q = 5/3 = -1.12
tan-1 -1.12 = -0.84
Q = -0.84
Q = -pi + -0.84 = -3.981
Polar form = 5.83e^(-3.981)i
ammontgo
Apr19-10, 11:25 AM
Ok first off:
I believe you've recorded your answer in exponential form.
Forms of Complex Numbers:
https://dl.dropbox.com/u/4645835/MATH/ComplexForms.gif
Please correct me if I'm wrong.
ammontgo
Apr19-10, 11:34 AM
I think your angle may be wrong as well. This is what I did:
https://dl.dropbox.com/u/4645835/MATH/Ex1.gif
I can explain why I added 180 degrees to the angle I calculated - if needed.
Hi
but as I know in this question we change calculator to ( Rad ) nor (deg) because we have integer number -3 and - 5 not roots or ,
and please I want explaine more because I don't understand clearly
write in polar form ...elc
-3 - 5i
my answer :
x = -3 y = - 5
r = root (-3)^2 + (-5)^2
= 5.83
tan Q = 5/3 = -1.12
tan Q = 5/3, but 5/3 is not equal to -1.12
tan-1 -1.12 = -0.84
Q = -0.84
Q = -pi + -0.84 = -3.981
Polar form = 5.83e^(-3.981)i
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